How to confirm the x-axis parameter of fimplicit's picture
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zhenyu zeng
el 25 de Jul. de 2019
Respondida: Walter Roberson
el 25 de Jul. de 2019
a=0.336;
Ta=9.476;
Te=1.208;
Tw=1.498;
eqh=[0.661,0.619,0.568];
ex=[-1.240,-1.346,-1.441];
en=-ex;
ey=[0.376,0.705,0.968];
eqx=[-0.309,-0.357,-0.392];
eh=[1.594,1.583,1.545];
exqh=en.*eqh+eqx.*eh;
eyqh=[0.642,0.78,0.897];
syms bt Td;
Kp=1./bt;
Ki=1./(bt.*Td);
a4=a*Ta*Te^2;
a3=Ta*Tw.*eqh+a*Te^2.*en+a*Te^2.*Kp.*ey;
a2=a*Te^2.*Ki.*ey+Ta+Tw.*exqh-Kp.*Tw.*eyqh;
a1=en+Kp.*ey-Ki.*Tw.*eyqh;
a0=Ki.*ey
for i=1:3
fimplicit(a1(i)*a2(i)*a3(i)-a1(i)^2*a4-a0(i)*a3(i)^2==0)
hold on
end
I get a picture from the codes above, but I can confirm x-axis' name. Is it bt or Td?
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Respuesta aceptada
Walter Roberson
el 25 de Jul. de 2019
fimplicit uses symvar(). The first variable output is used as the x axes.
symvar sorts the variable names according to byte values - so A before a and a10 before a2
T sorts before b so Td would be your x axes
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