How to vectorize assignment from array of structures to cell array

I am looking for a way to make an assignment from an array of structures to a cell array without using a loop.

Here is an example of what I am doing using a loop

% make up a very simple array of structures
s(1).pet = 'cat'
s(2).pet = 'fish'
s(3).pet = 'dog'

% would like to have a cell array listing the pets
% equivalent to the result of C1 = {'cat','fish','dog'}
% can get this using a loop
C1 = cell(1,3); % preallocate
for k = 1:3
  C1{k} = s(k).pet;
end

I unsuccessfully attempted to do without a loop

C2 = {s.pet};

But C2 is not the same as C1. It is a cell array with three elements each of which is a 1x1 cell array

So to summarize, my question. In the above example code how can I assign s(1).pet, s(2).pet and s(3).pet to a cell array C to give the result C = {'cat','fish','dog'} without using a loop?

p.s. If my usage of the term "array of structures" here is not correct please let me know.

Answer 1

[madhan ravi]

C = {s.pet} % is giving you the desired result already

[madhan ravi]

If you want to check if they are the same simply:

isequal(C1,C)

[Jon]

Yes you are right they are the same. So I guess my second method works after all. Apparently when I was doing this earlier I had made some other mistake with my test case and had incorrectly concluded that this didn't work. I should have tested the example I put up here.

Sorry for the confusing post.

Thanks for your help