How to fill a cell array without using a loop

Hi,

Assuming that we have an array of integers, for example a = [2 4 3], I am trying to create a cell array where each

cell contains arrays given by [-a(i) : 1 : a(i)] where a(i) is an arbitrary element i in the array a. So the example

a = [2 4 3] would result in a cell array c = {[-2 : 1 : 2], [-4 : 1 4], [-3 : 1 : 3]}.

I know how this can be done with a for loop but I was wondering if there is a way to do it without loops?

Answer 1

[madhan ravi]

I'm not sure of any other method but here is one with implicit loop:

c = arrayfun(@(x) -x:x, a,'un',0)
celldisp(c)

Or another method with accumarray():

c = accumarray((1:numel(a)).',a,[],@(x){-x:x})
celldisp(c)

Gives:

>> celldisp(c)
 
c{1} =
 
    -2    -1     0     1     2

 
 
c{2} =
 
    -4    -3    -2    -1     0     1     2     3     4

 
 
c{3} =
 
    -3    -2    -1     0     1     2     3

[radius236]

Thanks a lot, it works.