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Issues with the for loop

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Sophia
Sophia el 14 de Ag. de 2019
Cerrada: MATLAB Answer Bot el 20 de Ag. de 2021
tt=0;
for i = 1:size(ids_2006,2) * size od ids_2006 is 212*119*177
for j = 1:size(ids_2006,3)
tt=tt+1;
i,j,tt
% size of mean_wint_rho is 119*177
% size of stdv_daily_2006 is 119*177
if (squeeze(ids_2006(tt,:,:)) < (mean_wint_rho(:,:) - 3*stdv_daily_2006(:,:)))
daily_2006 = squeeze(ids_2006(:,i,j));
new_daily_2006(tt,:,:) = daily_2006;
%size of new_daily_2006 should be 212*119*177
else
new_daily_2006(tt,:,:) = NaN;
end
end
end
I want to remove the bias from the daily dataset by removing the points that are three standard deviation from the mean.

Respuestas (1)

darova
darova el 15 de Ag. de 2019
This should work
new_daily_2006 = ids_2006*0;
for i = 1:size(ids_2006,1) %* size od ids_2006 is 212*119*177
% i,j,tt
% size of mean_wint_rho is 119*177
% size of stdv_daily_2006 is 119*177
if (squeeze(ids_2006(i,:,:)) < (mean_wint_rho(:,:) - 3*stdv_daily_2006(:,:)))
new_daily_2006(i,:,:) = squeeze(ids_2006(i,:,:));
%size of new_daily_2006 should be 212*119*177
else
new_daily_2006(i,:,:) = NaN;
end
end
The question is: when it will be work?
if (squeeze(ids_2006(i,:,:)) < (mean_wint_rho(:,:) - 3*stdv_daily_2006(:,:)))
Something like this
if ([1 0])
disp('hi')
end
Or maybe this
if any([1 0])
disp('hi')
end
  3 comentarios
Sophia
Sophia el 16 de Sept. de 2019
I have finally figured the answer-
new_daily_2006 = [];
for t = 1:size(ids_2006,1)
for i = 1:size(ids_2006,2)
for j = 1:size(ids_2006,3)
temp = squeeze(ids_2006(t,i,j));
if (abs(temp) < stdv_daily_2006(i,j))
new_daily_2006(t,i,j) = temp;
else
new_daily_2006(t,i,j) = NaN;
end
end
end
end
darova
darova el 16 de Sept. de 2019
Editada: darova el 16 de Sept. de 2019
Try also without loops
m = size(ids_2006);
temp = reshape(stdv_daily_2006,[1 size(stdv_dayly_2006)]); % make 1 x 119 x 177
cond = abs(ids_2006) < repmat(temp,[m 1 1]) % make 212 x 119 x 177
new_daily_2006(cond) = ids_2006;
new_daily_2006(~cond) = NaN;

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