converting points on cell array

Hi I want to display points as cell. but it gives error at t

for i=0:n-1
    t=(find({Y2}=={(X(i+1))}));
    if (~isempty(t))
        temp=[ones(1,length(t)).*i; t-1];
        .
        .
        
        error at
        t=(find({Y2}=={(X(i+1))}));
       

 Undefined operator '==' for input arguments of type 'cell'

Can anyone tell me whats wrong here

[madhan ravi]

{Y2} why? Instead of Y2 ??, upload the missing datas.

[Walter Roberson]

What is your expectation for how {Y2}=={(X(i+1))} would work? Is there a reason you are not using Y2==(X(i+1)) ?

[sadiqa ilyas]

Y2={[]};X={[]}
for x=0:n-1
    Y2={[Y2 powermod(x,2,n)]};
    X={[X mod(x^3+a*x+b,n)]};
end
E=[];
for i=0:n-1
    t=(find({Y2})==({(X(i+1))}));
    if (~isempty(t))
        temp=[ones(1,length(t)).*i; t-1];
        E=[E temp];
    end
end

I want points in cell form

[sadiqa ilyas]

i want points appear in cell form.

[Are Mjaavatten]

What do you mean by points? And why use cell arrays?

I have modified your code so that it runs, but this may not be what you want. Could you explain in more detail what you are attempting to do?

n = 4;a = 1; b = 3;
Y2 = cell(n,1);X=cell(n,1);
for x=1:n
    Y2{x} = powermod(x,2,n);
    X{x}  = mod(x^3+a*x+b,n);
end
E=[];
for i=0:n-1
    t=find(cell2mat(Y2)==X{i+1});
    if (~isempty(t))
        temp=[ones(length(t),1)*i; t-1];
        E=[E temp];
    end
end

[sadiqa ilyas]

I am using cell because i am trying to do mapping using elliptic curves. The code you have written gives me points like

     0     1     2
     0     1     2
     0     0     0
     2     2     2