Creating a matrix having repeating elements

% Dear users,
% Assume that I have a A matrix having the size of 5x5 and in the end;
% I want to get A=[1 -1 0 0 0; 1 -1 0 0 0; 0 1 -1 0 0; 0 1 -1 0 0; 0 0 1 -1 0]
% What is the easiest way to do it?
% Thanks in advance

[Fabio Freschi]

Is this matrix what you want? I don't understand the structure

A =

     1    -1     0     0     0
     1    -1     0     0     0
     0     1    -1     0     0
     0     1    -1     0     0
     0     0     1    -1     0

[Rengin]

Yes, that's right! the element of (1,-1) should shift one column to the right in every odd row. If the row has an even number, it should repeat itself.

[Bruno Luong]

The easiest way is just type you matrix.

A=[1 -1 0 0 0; 1 -1 0 0 0; 0 1 -1 0 0; 0 1 -1 0 0; 0 0 1 -1 0]

[Rengin]

Since I can do it by myself, I am asking obviously something different.

[Bruno Luong]

OK here is different and still simple:

A=[1 -1 0 0 0; 1 -1 0 0 0; 0 1 -1 0 0; 0 1 -1 0 0; 0 0 1 -1 0]+0

The point is your question is not well formulated

[Rengin]

Thanks but I was still be able to get my answer. It works perfectly fine.

Answer 1

[Andrei Bobrov]

A = kron(eye(5),[1;1])+kron(diag(-ones(4,1),1),[1;1]);
out = A(1:5,:);

or

n = 1:5;
A = repmat([1,-1,0,0,0],5,1);
out = A(mod(repmat(n,5,1) - ceil(n(:)/2),5)*5 + n(:));

[madhan ravi]

You always impress without a doubt , a +1 from me.

[Andrei Bobrov]

Thank you Madhan!