How can i get sub matrices with using for loop
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Hello everyone
I have a matrix A as:
A=[1
1
1
1
1
1
1
1
1
1
2
2
2
2
2
2
2
2
2
2
3
3
3
3
3
4
4
4
4
4
5
5
5
5
5
6
6
6
6
6
7
7
7
7
7
7
7
7
7
7
8
8
8
8
8
8
8
8
8
8
9
9
9
9
9
9
9
9
9
9
10
10
10
10
10
10
10
10
10
10
11
11
11
11
11
11
11
11
11
11
12
12
12
12
12
12
12
12
12
12]
I get unique(A) as 12. And then i want to get new matrices as
for i=1, A(1) as row which is equal to i. And for i=2, A(2) as row which is equal to i.............for i=12 A(12) as rows which is equal to i.
For example:
A(1)=[1
1
1
1
1
1
1
1
1
1]
A(2)=[2
2
2
2
2
2
2
2
2
2]
A(3)=[3
3
3
3
3]
........
A(12)=[12
12
12
12
12
12
12
12
12
12]
How can i do this with using for loop or another way? I want to get new matrices as A(1) to A(12).
Respuesta aceptada
Más respuestas (1)
madhan ravi
el 17 de Sept. de 2019
a=arrayfun(@(x)A(A==unique(x)),A,'un',0)
celldisp(a)
If you’re goal is simply to create A with repetitions of 10 then it’s simply:
A = num2cell(repmat(1:12,10,1),1)
celldisp(A)
3 comentarios
Mooner Land
el 17 de Sept. de 2019
madhan ravi
el 18 de Sept. de 2019
How's this related to the question you originally asked?
Mooner Land
el 18 de Sept. de 2019
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