How to mix integers and chars in matrix?

1. I want to create the following matrix:

 A=[1 2 3 A B C]

2. After that, based on the matrix A, I want to generate random matrix of this following matrix:

A1=[1 3 2 A C B]
A2=[2 1 3 B A C]
A2=[2 3 1 B C A]

Does any body can help me?

[Paulo Silva]

Not possible inside matrix, you must use cells

Answer 1

[Sebastian]

As Paulo pointed out, this most likely requires usage of cells, e.g.:

>> A = {1 2 3 'A' 'B' 'C'};
>> A1 = A(randperm(6))

A1 = 

      [3]    'A'    [1]    'C'    [2]    'B'
>> A2 = A(randperm(6))

A2 = 

      [3]    [2]    'C'    'A'    'B'    [1]

However, if the integers and chars are always 1 digit/characte, then you can maybe also use the following approach:

>> a = '123ABC';
>> a1 = a(randperm(6))

a1 =

13A2CB

>> a2 = a(randperm(6))

a2 =

31BAC2

Answer 2

[zakri]

Thank you very much. I really appreciate it. However, how do we want to make the alphabet change according to the integer? for instance:

 Matrix A is :
A=[1 2 3 A B C]
where 
A (column 3) is dependant to 1 (column 0)
B(column 4) is dependant to 2 (column1)
C(column 5) is dependant to 3 (column 2)
if the integer 1, 2 and 3 is randomly permute within the columns
0 to 2, the alphabets of A,B and C are also randomly permute within columns 3 to 5.

Answer 3

[Sebastian]

Well, you could do something like

>> a = '123ABC';
>> l = size(a,2);
>> rp = randperm(l/2);
>> a1 = a([rp rp+l/2])

a1 =

321CBA

[zakri]

thank you. It helps me a lot.

Answer 4

[zakri]

hi again... How to repeatedly do random such: 321CBA 312CAB 213BAC

I type a code as the following:

 A='123ABC'
 AA=[];
randormsort=[];
 l=size(a,2);
 rp=randperm(l/2);
 for i=1:3
  AA(i,:)=A([rp rp+l/2]);
 end
randomsort=[AA];
however the result appear as follows: 
AA =
    49    51    50    65    67    66
    49    51    50    65    67    66
    49    51    50    65    67    66

the result that i am expected should be something like this:

3 2 1 C B A
2 1 3 B A C
2 3 1 B C A

[Paulo Silva]

char(AA)

[zakri]

it returns only

321CBA

[Paulo Silva]

find what's wrong with your code, that's the better way to learn.

[Paulo Silva]

hint: You got all the code in there but one line of it is in the wrong place :)

[zakri]

I have change to :

A='123ABC'

AA=[];

randormsort=[];

l=size(A,2);

rp=randperm(l/2);

for i=1:3

AA(i,:)=A([rp rp+l/2]);

end

randomsort=char(AA);

it works. however, the rows in the same value:

213BAC

213BAC

213BAC.

how to make it be in such a way that rows 2 and 3 are different sequence from rows 1?

[Paulo Silva]

You are only shuffling the cards once, that's why you get always the same result, shuffle the cards 3 times...

[zakri]

can you give a hint?

[Paulo Silva]

already did lol

c'mon you just need to put the randperm inside the loop, so easy :)

[zakri]

It works!!thank you.