Plotting 3 function using mesh command

I have to plot 3 functions in matlab using mesh command but donot know how to do it please anyone help me?

2 comentarios

Rik
Rik el 10 de Oct. de 2019
What is the full text of your homework assignment and what have you tried to find out so far?
qudsia Bashir
qudsia Bashir el 10 de Oct. de 2019
i solved an equation using 3 different method and now i want to plot the results obtained from these three methods.the function is of form u(x,y)

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Respuestas (1)

The best way to plot using mesh is to create three 2-D matrices with the same sizes.
x = 0:.1:1;
y = 0:.5:10;
[xq,yq] = meshgrid(x,y);
z = (xq.^2-yq.^2);
figure()
mesh(x,y,z)
Although 'x' and 'y' are different sizes, meshgrid creates a 2-D grid for xq and yq with the m rows and n columns where m equals the length of y and n equals the length of x.
I find the easiest way to think of it is this way:
a 3-D plot needs values for each x, y, and z position. 'xq' is the x coordinates for each point. 'yq' is the y coordinates for each point, and 'z' is the z-coordinates for each respective point. So you create a 2-D grid and give each point some height 'z'.
You do not need to use meshgrid to create your initial 2D matrices, but I find it works well for most cases.

4 comentarios

qudsia Bashir
qudsia Bashir el 10 de Oct. de 2019
thanks but i want to know how to plot 3 functions in space using mesh command
Rik
Rik el 10 de Oct. de 2019
Just as with any other plotting function: if you want to have more than one, you have to adjust the NextPlot property. The easiest way to do this is to use hold on.
qudsia Bashir
qudsia Bashir el 12 de Oct. de 2019
i am using the code given below but its giving error that dimmension must agree i have cross check the dimmensions are the same of both functions donot know y this is happening syms x t
for K=1:20
D(1,K)=0 ;
end
for K=1:19
for h=0:19
A(K+1,h+1)=(pi).^(K+2*h);
B(K+1,h+1)=sind(((K+2*h)*180)/2)
D(K+1,h+1)=A(K+1,h+1)*B(K+1,h+1)/(factorial(K)*factorial(h));
end
end
s=0;
for i=1:18
for j=1:18
x=0.2:0.2:0.8;
s=s+D(i,j).*x.^(i-1).*t.^(j-1);
end
end
t=0:0.1:0.5;
sia=subs(s,t);
sia1=eval(subs(s,t));
t=0:0.1:0.5;x=(0.2:0.2:0.8)';
exact1 = bsxfun(@times,sin(pi*x),exp(-(pi)^2*t));
B = reshape(exact1',[],1);
exact=B';
errordtm=abs(exact-sia1);
dtmmatrix = vec2mat(sia1,6);
mesh(x,t,exact1,'edgecolor', 'b');
hold on
mesh(x,t,dtmmatrix,'edgecolor', 'r');
legend({'Numerical','Exact'})
hold off
the length of your vector 'x' is 4, the length of your vector 't' is 6. just fix these dimensions to match. I suggest using linspace for t using the length of vector x.
I also would suggest initializing D using zeros.
D = zeros(20,1);

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el 10 de Oct. de 2019

Editada:

el 13 de Oct. de 2019

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