Grouping similar element based on common columns

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Poulomi Ganguli
Poulomi Ganguli el 22 de Oct. de 2019
Editada: Poulomi Ganguli el 23 de Oct. de 2019
Hello:
I have two matrices, which I wish to group together based on common first three column elements. If no common column element found, it should be filled by 'NaN' element. Here is the two matrices A and B and resulting matrix C after the operation:
A = [6119200 44.55 -0.87 0.91
6123400 47.05 0.54 0.68
6122141 49.55 2.99 0.39
6421500 50.87 5.72 0.54
6607851 51.25 0.45 0.72]
B = [6123400 47.05 0.54 1.14
6122141 49.55 2.99 0.75
6421500 50.87 5.72 0.73
6607851 51.25 0.45 0.70
6607851 51.25 0.45 0.26
6607650 51.41 0.31 0.47]
C = [6119200 44.55 -0.87 0.91 NaN
6123400 47.05 0.54 0.68 1.14
6122141 49.55 2.99 0.39 0.75
6421500 50.87 5.72 0.54 0.73
6607851 51.25 0.45 0.72 0.26
6607650 51.41 0.31 0.47 NaN]
Any help how should I do so?
  3 comentarios
Daniel M
Daniel M el 22 de Oct. de 2019
What about the 4th and 5th row in B? One of them is dropped.
6607851 51.25 0.45 0.70
6607851 51.25 0.45 0.26
Poulomi Ganguli
Poulomi Ganguli el 23 de Oct. de 2019
A and B are the two matrices, C is the desired output after merging matrices A and B.

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Respuesta aceptada

Sebastian Bomberg
Sebastian Bomberg el 23 de Oct. de 2019
You can use outerjoin:
% Convert matrices A and B to tables
TA = array2table(A,"VariableNames",["Key"+(1:3) "A"])
TB = array2table(B,"VariableNames",["Key"+(1:3) "B"])
% Perform outerjoin with respect to columns 1 to 3 as key variables
TC = outerjoin(TA,TB,"Keys",1:3,"MergeKeys",true,"Type","full")
% Convert result back to matrix C
C = table2array(TC)
Note that in your C matrix, the 2nd NaN will appear in the second to last column with the values originally in matrix A.
Also, as Daniel M pointed out, both rows with identical keys will show up in the joined table.
  1 comentario
Poulomi Ganguli
Poulomi Ganguli el 23 de Oct. de 2019
Editada: Poulomi Ganguli el 23 de Oct. de 2019
TA = array2table(A,'VariableNames',{'Key1','Key2','Key3','A'});
>> TB = array2table(B,'VariableNames',{'Key1','Key2','Key3','B'});
>> TC = outerjoin(TA,TB,"Keys",1:3,"MergeKeys",true,"Type","full")

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