how to solve a linear equation

hi, I am solving continuous markov chain state equation. Following is the code of those equations.

how can I get the equations (as example P0 - T(1,:)* [P0; P1 ;P2; P3] = 0) after % equations section?

Thanks

syms P0 P1 P2 P3                    % stable state
syms u03 lamda13 lamda20 lamda21 u32

T= [1-u03           0               0                       u03;
        0           1-lamda13       0                       lamda13;
    lamda20         lamda21         1-lamda20-lamda21       0;
        0               0           u32                     1-u32];

% equations
P0=T(1,:)* [P0; P1 ;P2; P3];
P1=T(2,:)* [P0;P1;P2;P3];
P2=T(3,:)* [P0;P1;P2;P3];
P3=T(4,:)* [P0;P1;P2;P3];

Answer 1

[Sulaymon Eshkabilov]

Hi,

Here is the solution:

syms P0 P1 P2 P3                    % stable state
syms u03 lamda13 lamda20 lamda21 u32
T= [1-u03           0               0                       u03;
        0           1-lamda13       0                       lamda13;
    lamda20         lamda21         1-lamda20-lamda21       0;
        0               0           u32                     1-u32];
% equations
E0=T(1,:)* [P0; P1 ;P2; P3];
E1=T(2,:)* [P0;P1;P2;P3];
E2=T(3,:)* [P0;P1;P2;P3];
E3=T(4,:)* [P0;P1;P2;P3];
% EQNS
    EQN0 = P0- E0;
     EQN1 = P1- E1;
      EQN2 = P2- E2;
       EQN3 = P3- E3;
       
       

Good luck

[Kazi Main Uddin Ahmed]

Thanks a lot,

[Sulaymon Eshkabilov]

You are welcome. Just a pleasure to be of some help.