matlab code running problem

I am trying to run following code on matlab 7.7.0 but it consumes too much time and No output !

for i=1:length(data);
  j=1:length(data);
  if y1(i)>1.2
    f(j)=y1(i);
  end
end

it also can not be run on matlab 6 though the developer said that it works on matlab 6.

[Daniel Shub]

Please format your code. Are you sure your code is correct? Are you missing a for loop (over j). Can you tell use about data, y1 and f? What do you expect to see and what do you see. How long is "too much time"

[Jan]

Why do you claim that this piece of code does not run under Matlab 6?

Answer 1

[Jan]

It is not clear what your code should do. Creating "1:length(data)" in each iteration is a waste of time. In addition you overwrite the elements of f most likely.

Did you forget a "for" before "j=..."?

What do you want to achieve?

Answer 2

[Javier]

Hello Mali

What is the purpose of this code ??? Does the variable j change size in each iteration ? If not, do not define it. I believe that you define "j" to establish the size of f. Something that could work better:

j=size(data,1) % for column vector

If want to find the elements in y1 that are greater than 1.2

[r,c,i]=find(y1>1.2); Now you have the row, column and index value that match the search

Now you have the data, What you want to do with them ???

Hope it helps