How to write umax*exp(1./((th-th0).*(th-th1)))/en for th0<th<th1 in matlab?
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Kayode Odeyemi
el 7 de Nov. de 2019
Comentada: Walter Roberson
el 7 de Nov. de 2019
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I saw something related to my question
uu = @(th) vif(th>ph0&th<ph1,umax*exp(1./((th-ph0).*(th-ph1)))/en,0)
but unfortunately, 'vif' is not defined. Please I need clarification.
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Walter Roberson
el 7 de Nov. de 2019
Editada: Walter Roberson
el 7 de Nov. de 2019
Assuming that you have assigned a definite vector of values to th, then:
y = nan(size(th));
mask = th0 < th & th < th1;
y(mask) = umax*exp(1./((th(mask)-th0).*(th(mask)-th1)))/en;
2 comentarios
Walter Roberson
el 7 de Nov. de 2019
Why do you want to write it that way?
Have you considered using piecewise() from the symbolic toolbox?
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