IF statement and time display
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Dear All
I have a string which displays time and date taken from a txt file using:
str= datestr(datenum([yy mm dd HH MM SS]),0);
output yy =
96
96
96
97
98
99
00
01
I want it to be displayed as 1996 if it is before 2000 and 2000,2001,2002,..so on if after 2000.
Also the 'mm' format being displayed is like Jan,feb,.. can it be displayed as 01,02,03,..12? I couldn't find the proper formatting for it.
Current output example: str = 20-Dec-0003 22:47:39
Thanks
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Respuesta aceptada
Andrei Bobrov
el 26 de Sept. de 2012
Editada: Andrei Bobrov
el 26 de Sept. de 2012
x= {'96318.74847837'
'96319.62211352'
'96319.62351606'
'96319.62356237'
'96320.05952563'
'96320.49676119'} % initial array
a = str2double(x);
y = fix(a/1000);
ymdhms = datevec(datenum(y,0,a - y*1000)); % corrected
[yearnow,~] = datevec(now);
ymdhms(:,1) = (ymdhms(:,1) <= rem(yearnow,2000))*100 + 1900 + ymdhms(:,1);
out = datestr(ymdhms,'yyyy-mm-dd HH:MM:SS');
5 comentarios
Andrei Bobrov
el 26 de Sept. de 2012
Hi Hamza! Excuse me, I use year as function from the Financial Toolbox. Corrected.
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