Wrong answer for sine function
1 visualización (últimos 30 días)
Mostrar comentarios más antiguos
Ellen Brown
el 17 de Nov. de 2019
Comentada: Star Strider
el 17 de Nov. de 2019
I am trying to create a function to evaluate sine at different values of t
function F = rforce(t)
F = 0.3 + 0.2.*sin(2.*pi.*t/365 - pi/2);
end
but this gives the incorrect answer when ran in matlab
2 comentarios
Star Strider
el 17 de Nov. de 2019
It would appear that the units of ‘t’ are days, so ‘F’ would be with respect to years (or fractions of years).
What result do you want?
Respuesta aceptada
Star Strider
el 17 de Nov. de 2019
Define ‘t’ in terms of days (or fractions of days).
Try this:
rforce = @(t) 0.3 + 0.2.*sin(2.*pi.*t/365 - pi/2);
tdays = 1:0.25:365.25; % One Year in 6-Hour Increments
figure
plot(tdays, rforce(tdays))
grid
xlabel('Days')
ylabel('r Force')
xlim([min(tdays) max(tdays)])
2 comentarios
Más respuestas (0)
Ver también
Categorías
Más información sobre Logical en Help Center y File Exchange.
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!