Can any one explain the following to me?

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Dhiyaa Al-Shammari
Dhiyaa Al-Shammari el 10 de Dic. de 2019
Comentada: Dhiyaa Al-Shammari el 10 de Dic. de 2019
If I have an ECG signal its samples =3600 sample / second , sample rate Fs=360 Hz, Recording time = 30 minute for this signal as they said in te papers and also in the website database MIT-BIH dataset in the physionet.
so I Want to understand when I divide # of Sample / FS====> 3600/360=10 sec, I faced a problem in understanding the time its not compatible with the time as mentiond in MIT-BIH datset ,which that equals 30 minute.
I need anyone to understand me where is the problem.
  2 comentarios
Star Strider
Star Strider el 10 de Dic. de 2019
This is ambiguous. The sample rate is either 3600 Hz (that I doubt) or 360 Hz (reasonable). A 30-minute recording with 360 Hz Fs should have 648000 samples. Check the vector size to be certain.
Which record is this? It would not be difficult to go online to check it and resolve the problem.
Dhiyaa Al-Shammari
Dhiyaa Al-Shammari el 10 de Dic. de 2019
Please you can help me when you read the following ,I read it but I want understand more because there is a conflection .
this link explain the details of the dataset , here the following link :
Here some details about the dataset(MIT-BIH arrhythmia dataset [28] is used in this paper. It contains 48 half-hour records obtained from 47 subjects and extracted from two leads (lead II (MLII) and lead V1). Each of the 48 records is slightly over 30 minutes long. The subjects were 25 men aged 32 to 89 years, and 22 women aged 23 to 89 years. The recordings were digitized at 360 samples per second per channel with 11-bit resolution over a 10-mV range. MIT–BIH arrhythmia database is divided into two classes, normal 25 ECG records and abnormal 23 ECG records. In this paper, the algorithm is tested on the ECG signals taken from lead II (MLII) ).
Also I will attach you the intended file and all the file of the dataset you can check it from MIT-BIH database, so I attached the file with one chanall because the orginal file contains two channel .

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