# Truncate a two dim array based on contents of a particular column

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Oindri on 12 Dec 2019
Edited: Ridwan Alam on 12 Dec 2019
I have an array whose number of rows can vary but cols are 34. One of the cols, 12th, has values 0,1,2 & 3. There is no set pattern as to how many times any of them can occur in one such array. Also, there is no exact distribution of rows with 12th col = 0/1/2/3, it may happen that 4 rows have 0, next 10 rows have 1, next 7 rows have 2 and last three rows have 3. My requirement is, how to truncate the array based on 12th col value being, either 0 or 1 or 2 or 3. Any help is appreciated !

JESUS DAVID ARIZA ROYETH on 12 Dec 2019
could you give us a little example with desired input and output ?
Guillaume on 12 Dec 2019
Is the aim to split the array into arrays based on the values in column 12?

Ridwan Alam on 12 Dec 2019
N = input('Number of rows: ');
A = rand(N,34);
A(:,12) = randi([0 3],N,1);
% simple version if 12th col only always has 0,1,2,3
A0 = A(A(:,12)==0,:);
A1 = A(A(:,12)==1,:);
A2 = A(A(:,12)==2,:);
A3 = A(A(:,12)==3,:);
% for a more general version, use unique() on 12th col and do it in a loop for simplicity
Hope this helps!

Guillaume on 12 Dec 2019
Even for just 4 categories, don't do that!
You're just encouraging bad programming patterns with your numbered variables and you can be sure that at some point there'll be more categories and the same pattern will continue to be used.
g = findgroups(A(:, 12)); %group identical elements of column 12
split = splitapply(@(rows) {A(rows)}, (1:size(A, 1))', g); %split A into cell array according to group
is simpler anyway.
Ridwan Alam on 12 Dec 2019
Indeed. I was trying to go there with the lead to using unique().
Also, I was just trying to answer as "simply" as possible, given "simple" is relative. :)