New variables in a loop

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Ancalagon8
Ancalagon8 el 25 de Dic. de 2019
Comentada: KALYAN ACHARJYA el 25 de Dic. de 2019
Hello everyone! I'm facing some issues while trying to create new variables inside a for loop. Here is the first part of my code. My question is wheter i can load my data using a for loop while keeping first character (m) and changing 15,20,25,30 and A,B,C....J.
load m15A
load m15B
load m15C
load m15D
load m15E
load m15F
load m15G
load m15H
load m15I
load m15J
load m20A
load m20B
load m20C
load m20D
load m20E
load m20F
load m20G
load m20H
load m20I
load m20J
load m25A
load m25B
load m25C
load m25D
load m25E
load m25F
load m25G
load m30A
load m30B
load m30C
load m30D
load m30E
load m30F
load m30G
load m30H
My second question is how can i assign new variables winside a for loop. I tried something like this but did not worked:
for i=1:35
Fs_{i}=(L(i)/tmax(i));
end
for j=1:35
for k=15:5:35
t{j}=m(k)A(:,1);
acc{j}=m(k)A(:,2);
end
end
Thanks in advance!
L1=length(m15A);
t_max1=max(m15A(:,1));
L2=length(m15B);
t_max2=max(m15B(:,1));
L3=length(m15C);
t_max3=max(m15C(:,1));
.....
.....
.....
L34=length(m30G);
t_max34=max(m30G(:,1));
L35=length(m30H);
t_max35=max(m30H(:,1));
%% Calc sampling frequency
Fs_1=L1/t_max1;
Fs_2=L2/t_max2;
Fs_3=L3/t_max3;
........
........
........
Fs_34=L34/t_max34;
Fs_35=L35/t_max35;
%% Assign Collumns
t1=m15A(:,1);
acc1=m15A(:,2);
t2=m15B(:,1);
acc2=m15B(:,2);
......
......
......
t35=m30H(:,1);
acc35=m30H(:,2);

Respuestas (1)

KALYAN ACHARJYA
KALYAN ACHARJYA el 25 de Dic. de 2019
Editada: KALYAN ACHARJYA el 25 de Dic. de 2019
Considering the array or cell array is best way rather than assigning new variable in each iteration.
Fs=zeros(1,35);
for i=1:35
Fs(i)=L(i)/tmax(i); % assuming L and tmax both are scalars
end
% Assuming L and tmax both are scalars, if not then
Fs=cell(1,35);
for i=1:35
Fs{i}=L(i)/tmax(i);
end
  2 comentarios
Ancalagon8
Ancalagon8 el 25 de Dic. de 2019
i get message: Undefined function 'L' for input arguments of type 'double'.
KALYAN ACHARJYA
KALYAN ACHARJYA el 25 de Dic. de 2019
It's your code, I have just modified, what is L? Please define.

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