"Index exceeds the number of array elements"
2 visualizaciones (últimos 30 días)
Mostrar comentarios más antiguos
Tom Keaton
el 29 de En. de 2020
Comentada: Tom Keaton
el 4 de Feb. de 2020
Hello,
I am recieving this error:
Index exceeds the number of array elements (1).
Error in sym/subsref (line 890)
R_tilde = builtin('subsref',L_tilde,Idx);
Error in E_field (line 7)
Ey = matlabFunction(E(2));
Here is the function file the error is referencing:
function [Ex, Ey, Ez] = E_field()
syms x y z
R_s = 0.02;
V = 0;
epnaut = 8.854187E-12;
k = 1/(4*pi*epnaut);
Q = (V*R_s)/k;
r = [x, y, z];
E = (k*Q/norm(r)^3)*r;
Ex = matlabFunction(E(1));
Ey = matlabFunction(E(2));
Ez = matlabFunction(E(3));
end
1 comentario
Walter Roberson
el 29 de En. de 2020
The posted code works for me. However you should using the 'vars' option of matlabFunction or else your function handle is not going to accept any arguments because your R values are all constants.
Respuesta aceptada
Matt J
el 29 de En. de 2020
Editada: Matt J
el 29 de En. de 2020
Perhaps this is what you are looking for,
function [Ex, Ey, Ez] = E_field(x,y,z)
R_s = 0.02;
V = 0;
epnaut = 8.854187E-12;
k = 1/(4*pi*epnaut);
Q = (V*R_s)/k;
r = [x, y, z];
E = (k*Q/norm(r)^3)*r;
Ex = E(1);
Ey = E(2);
Ez = E(3);
end
9 comentarios
Walter Roberson
el 1 de Feb. de 2020
Is there a reason you are using global instead of persistent ? Is there some other function that will use the created Bx By Bz Ex Ey Ez ?
Más respuestas (1)
Walter Roberson
el 1 de Feb. de 2020
V = 0;
V is 0.
Q = (V*R_s)/k;
V is 0, so Q will be 0.
E = (k*Q/norm(r)^3)*r;
Provided that norm(r ) is not 0 and k is not infinity, then because Q is 0, E is going to be
zeros(size(r))
symvar() of a vector of 0 is empty. matlabFunction() of a constant, when you do not use any 'vars' option, is a function handle that accepts no inputs and returns a scalar copy of the constant.
The original code that was posted does not give me an index exceeded matrix dimension when I test it in R2019a.
Ver también
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!