Borrar filtros
Borrar filtros

How can I plot multiple iteration loglog graphs.

3 visualizaciones (últimos 30 días)
Alex Manuel
Alex Manuel el 24 de Mzo. de 2020
Comentada: Alex Manuel el 28 de Mzo. de 2020
N0 = 1*10.^9;
n = 3;
T=365*24*3600;
Table = cell(n, 4);
t = logspace(1, 7);
A = logspace(-22,-1);
ylabel('Activity /s^.-1');
xlabel('t');
set(gca,'xscale','log')
L(1) = 4.979*10.^-18;
L(2) = 3.329*10.^-7;
L(3) = 2.874*10.^-5;
for i=2:n
Bsum=0;
for t = 1:1*10.^5:T
Prod1 = 1;
for l = 1:i-1
Prod1 = Prod1*L(l);
end
for j = 1:i
Prod2 = 1;
for k = 1:i t
if k ~= j
Prod2 = Prod2*(L(k) - L(j));
end
end
Sum = Ssum+exp(-L(j)*t)/Prod2;
end
F = Sum*Prod1*N0;
A = Sum*L(i);
Table(i, :) = {i t F A };
fprintf('%d %d %d %d\n', Table{i, :, :});
end
end
My Scipt needs to output graphs for each iteration of i in terms of A against t, at the moment it will do it to i=3 but if I need to more I would like it to automatically plot the graphs like the subplot command.
Currently my code for my graph only outptus the whole of the iteration from 1:3 rather than each iteration
Activity = logspace(-22,-1);
loglog(A,t,'-o')
line(A, t)
Any help will be great!

Respuesta aceptada

Sindhu Karri
Sindhu Karri el 27 de Mzo. de 2020
You can try using nexttile which is similar to subplot
By using nexttile, loglog inside the for loopyou will be able to plot the graph of (A,t) for each iteration.
Refer to the below link:
  1 comentario
Alex Manuel
Alex Manuel el 28 de Mzo. de 2020
I've run into a problem where only my last value is used, how would I go about plotting each A at each t step for a specific iteration?
i t A Sum
3 310 8.251044e-09 2.371350e-13
3 311 8.330961e-09 2.394318e-13
3 312 8.411392e-09 2.417434e-13
3 313 8.492338e-09 2.440698e-13
3 314 8.573802e-09 2.464111e-13
3 315 8.655785e-09 2.487673e-13
3 316 8.738288e-09 2.511384e-13
It looks like this, where only the very last value is used on the graph.
i t A Sum
3 316 8.738288e-09 2.511384e-13

Iniciar sesión para comentar.

Más respuestas (0)

Categorías

Más información sobre Line Plots en Help Center y File Exchange.

Etiquetas

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by