solving for simple Integration symbol
3 visualizaciones (últimos 30 días)
Mostrar comentarios más antiguos
A C
el 10 de Abr. de 2020
Editada: David Goodmanson
el 10 de Abr. de 2020
When integrate for rho in this equation b/(1-b*rho), I get -log(b*rho-1) which is wrong. It should come out to be -log(1-b*rho).
My code:
syms A B Z a b R T rho
q1 = b/(1-b*rho)
I1 = int(q1,rho)
I1 = - log(b*rho - 1)
0 comentarios
Respuesta aceptada
David Goodmanson
el 10 de Abr. de 2020
Editada: David Goodmanson
el 10 de Abr. de 2020
HI AC
d/drho (-)*log(b*rho-1) = (-)*1/(b*rho-1)*b = b/(1-b*rho) = q1
so it is correct. But your result is correct as well.
Ignoring the (-) in front for the moment, your result is
log(1-b*rho) = log((-1)*(b*rho-1)) = log(b*rho-1) + log(-1)
= log(b*rho-1) +i*pi
which differs from the 'int' result by a constant of integration i*pi. Whichever result you want to use would usually be decided by keeping the argument of the log function to be positive.
0 comentarios
Más respuestas (0)
Ver también
Categorías
Más información sobre Equation Solving en Help Center y File Exchange.
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!