Problem Using Interp1 Within For Loop

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Jonathan Pinko
Jonathan Pinko el 30 de Abr. de 2020
Comentada: Ameer Hamza el 1 de Mayo de 2020
I have the following code:
xq = dataset(1:116,1);
Fevq = zeros(length(xq),length(Fes));
for l=1:numel(Fes);
Fevq(l)=interp1(Fo(:,l),DeltaFe56(:,l),xq);
end
Fes is a 2x1 matrix, and both Fo and DeltaFe56 are both 126x2 matrices. I would like to interpolate the values of xq onto the (Fo,DeltaFe56) curves both when l=1, and when l=2. When I try to do this, however, I get the error message, "Unable to perform assignment because the left and right sides have a different number of elements".
I would like both sides to have the size of 116x2, and I am not sure why this isn't the case. Can anybody explain why this isn't working?
Thanks,
Jonathan

Respuesta aceptada

Ameer Hamza
Ameer Hamza el 1 de Mayo de 2020
Try this
xq = dataset(1:116,1);
Fevq = zeros(length(xq),length(Fes));
for l=1:numel(Fes);
Fevq(:,l)=interp1(Fo(:,l),DeltaFe56(:,l),xq); % use Fevq(:,l) to indicate that you want to assign value to a column
end
  2 comentarios
Jonathan Pinko
Jonathan Pinko el 1 de Mayo de 2020
This works perfectly, what a silly mistake on my part!
Thanks,
Jonathan
Ameer Hamza
Ameer Hamza el 1 de Mayo de 2020
I am glad to be of help.

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