Poisson Process for 500 variates
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I would like to generate a code to produce a poisson process for N = 500 variates witk k is randomly between 1 and 10 and lambda = 12.
N = 500;
T = 1;
lambda = 12;
t = linspace(0, T, 100);
dt = t(2) - t(1);
S=cumsum([zeros(1,N); poissrnd(lambda*dt, length(t)-1, N) ]);
plot(t,S)
I generated this code by myself, bu I cannot use the random value of k between 1 and 10 , and 500-variates graph has too many lines, but I guess this result is totally wrong, how can I get rid of my mistakes and write the code properly?
Thanks a lot.
My second code is this
T = 1;
lambda = 12;
k=9;
t = linspace(0, T, 500);
for i = 1:500
f(i) = (lambda.^k) .* exp(-lambda) ./ factorial(k);
end
N = cumsum(f);
disp(N)
stairs(t,N(1:100))
But, again, the graph and estimations are totally wrong.
Respuesta aceptada
Más respuestas (3)
Sulaymon Eshkabilov
el 14 de Mayo de 2020
Here is the alternative solution:
T = 1;
lambda = 12;
t = linspace(0, T, 500);
k=randi([1,10], 500);
f = (lambda.^k) .* exp(-lambda) ./ factorial(k);
N = sum(f);
disp(N);
stairs(t,N)
Good luck
Sulaymon Eshkabilov
el 14 de Mayo de 2020
0 votos
Why not to use MATLAB's built in fcn: poissrnd()
3 comentarios
Le Duc Long
el 25 de Jun. de 2020
Hi Sulaymon Eshkabilov and Zeyneh Toprak,
I am also interested in this issue. My problem is to get the number of vehicles to an intersection with the Poisson distribution, lambda = 0.5 (vehicle/second). Can you help me code for vehicle traffic (numbers of vehicles) distributed by time period 500 seconds, step of time = 1 second?
Thanks so much!
Sa'adatu Abubakar
el 29 de Jul. de 2021
Hello I'm also interested in the area please can you help me with the MATLAB code for poison arrival and general servive with single server?. Thank you
Sa'adatu Abubakar
el 29 de Jul. de 2021
please I mean poisson arrival with general service and single server.
Najme Benvari
el 23 de Mayo de 2023
0 votos
Hi I read the Poisson production code when the jump size is random and the intensity of the jumps is Stochastic and a CIR process. I will be very thankful.
1 comentario
Najme Benvari
el 25 de Mayo de 2023
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