# Compare values and create new vector

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Rene el 30 de Ag. de 2020
Comentada: Rene el 30 de Ag. de 2020
Hello guys
I have two matrices
A:
1 162.880000000000
2 270.270000000000
3 341.660000000000
4 435.050000000000
5 535.590000000000
6 559.990000000000
7 625.190000000000
8 674.740000000000
9 762.620000000000
10 949.380000000000
11 1137
12 1361.90000000000
13 1460.10000000000
14 1517
15 1631.30000000000
16 1746.70000000000
17 1770.60000000000
18 1841.70000000000
19 1843.50000000000
20 1905.10000000000
and B:
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
19
17
18
19
20
Now I want a new vector that has the values of the second row of A in the order like so: (the first row is just there for understanding how to sort the vector)
%B Matching value from second row of A
1 162.880000000000
2 270.270000000000
3 341.660000000000
4 435.050000000000
5 535.590000000000
6 559.990000000000
7 625.190000000000
8 674.740000000000
9 762.620000000000
10 949.380000000000
11 1137
12 1361.90000000000
13 1460.10000000000
14 1517
15 1631.30000000000
16 1746.70000000000
19 1843.50000000000
17 1770.60000000000
18 1841.70000000000
19 1843.50000000000
20 1905.10000000000
So I want to compare the first rows of A and B and if the number matches, put the value of the second row of A in.
I already tried this, but this will stop as soon as the value is unequal (so after 16 here).
for i=1:size(A,1)
if B(i,1) == A(i,1)
new(k,1) = A(i,2);
k = k+1;
end
end
How can I say matlab to go on and compare further?
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KSSV el 30 de Ag. de 2020
It seems you want interp1. Let A be your m*2 matrix and B be n*1.
iwant = interp1(A(:,1),A(:,2),B)
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Rene el 30 de Ag. de 2020
Thank you very much. This worked perfectly.
It's so easy when you know the right commands.

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