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Creating an array within a for loop

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Timothy Russell
Timothy Russell el 27 de En. de 2013
I have a plotting function which gets the points to plot from a for loop, i.e.
for i=1:length(rat2ind)
ind = A(:,1)==A(rat2ind(i),1); % pick all the rat locs for rat i
plot(A(ind,2),A(ind,3),randcolor);axis([-0.5 7.5, -0.5 7.5]) % plot rat i trajectory
hold on;
end
but instead of plotting the points, I'd like to save the points in an (n,2) array. I tried this:
for i=1:length(rat2ind)
ind = A(:,1)==A(rat2ind(i),1);
H=vertcat(H,[A(ind,1),A(ind,2),A(ind,3)]);
end
but it gave me a variable which is definitely not what I needed as its twice as large as my original data (the data, and my actual goal isn't really relevant here)
Thanks for any help
  4 comentarios
Cedric
Cedric el 27 de En. de 2013
This line is suspicious to me:
ind = A(:,1)==A(rat2ind(i),1);
are you sure that it is not:
ind = A(:,1) == rat2ind(i) ;
Timothy Russell
Timothy Russell el 28 de En. de 2013
changing this gives me exactly the same wrong answer...!

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Respuesta aceptada

Timothy Russell
Timothy Russell el 28 de En. de 2013
Thanks for the help, turns out that this function is exactly what I wanted:

Más respuestas (1)

Matt J
Matt J el 27 de En. de 2013
Editada: Matt J el 27 de En. de 2013
N=size(A,1);
map=double(bsxfun(@eq,sparse(A(:,1)),A(ratind,1).'));
ind=nonzeros( bsxfun(@times, (1:N).', map ) );
H=A(ind,1:3);
  3 comentarios
Matt J
Matt J el 29 de En. de 2013
Editada: Matt J el 29 de En. de 2013
Yeah, I see that now. My guess is that it's because, as Cedric pointed out, you probably really want to be comparing with ratind instead of A(ratind,1).
Timothy Russell
Timothy Russell el 2 de Feb. de 2013
Yeah you're right, sorry. The confusion came from trying to use exactly the same method in my plotting function, and forgetting what the variables actually represented. Thanks alot for the help, i'm actually starting to enjoy using matlab!_

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