Error solving three equations in three unknowns

syms Tan Man Lan eqns vars L av bv cv
Tan =- b - 2 == 0;
Man = c + 1 == 0;
Lan = a + b - 3*c - 1 == 0;
eqns = [Tan Man Lan];
vars = [a b c];
L = solve(eqns,vars,'ReturnConditions',true)
av=L.a
bv=L.b
cv=L.c
Error is Empty sym: 0-by-1

5 comentarios

Which release are you using. I get following result
syms Tan Man Lan eqns vars L av bv cv b c a
Tan =- b - 2 == 0;
Man = c + 1 == 0;
Lan = a + b - 3*c - 1 == 0;
eqns = [Tan Man Lan];
vars = [a b c];
L = solve(eqns,vars,'ReturnConditions',true)
Result
>>
av=L.a
bv=L.b
cv=L.c
av =
0
bv =
-2
cv =
-1
The online version at https://matlab.mathworks.com/
Ameer Hamza
Ameer Hamza el 25 de Oct. de 2020
Even in MATLAB online, I am getting the correct result. Can you copy and paste the code in my answer and run it?
The only diff I used
Tan=simplify((solve(S==(T^f),f)))==0
Man=simplify((solve(S1==(M^f),f)))==0
Lan=simplify((solve(S2==(L^f),f)))==0
eqns = [Tan Man Lan];
vars = [a b c];
L = solve(eqns,vars,'ReturnConditions',true);
Instead of writing the equations
The answer =
a: [0×1 sym]
b: [0×1 sym]
c: [0×1 sym]
parameters: [1×0 sym]
conditions: [0×1 sym]
First, I would point out you seem to think you need to define all of your variables.
syms Tan Man Lan eqns vars L av bv cv
Yet ALL of those variables were defined later.
In fact, the only variables in your code that you never defined as symbolic, were the ones you really need to define! That is, a,b,c all need to be created as symbolic variables, you you never did that.

Iniciar sesión para comentar.

Respuestas (1)

syms a b c
Tan = -b - 2 == 0;
Man = c + 1 == 0;
Lan = a + b - 3*c - 1 == 0;
[av,bv,cv] = solve(Tan,Man,Lan,a,b,c)
av = 
0
bv = 
2
cv = 
1
This is a linear system, so there is no need even to specify the returnconditions.
As you can see, the only thing I needed to define as symbolic were the variables a,b,c. Everything else is then derived from them.

Categorías

Más información sobre Symbolic Math Toolbox en Centro de ayuda y File Exchange.

Productos

Preguntada:

el 25 de Oct. de 2020

Respondida:

el 25 de Oct. de 2020

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by