What does this print out?

a = 3;

b = a;

a = 1;

while (b<a)

   b = b + 1;        
   disp(b)
end

I thought this would create an infinite loop is that correct?

Answer 1

[Paulo Silva]

it never prints, the condition is false

do this before the loop

b<a %replacing b and a by their first values you get 3<1

answer is 0 because the condition is false thus the loop never begins

[Cote]

is it false because it always says 3<1 ?

[Cote]

So does it cause an infinite loop since it is a while loop and the condition is never met?

[Paulo Silva]

the condition is tested in the while line, if true the while begins, does what's inside it and in the end it tests again the condition, if false the code inside the while loop is "ignored"