I want to know how to convert these lines of code into c

fs = 70e6;           % sampling frequency
b = 25e6;    % bandwidth
trans_freq = 9.375e9;  % Carrier frequency
sweep_time = 1e-3;    % sweep time
total_sweeps = 4;
t=0:1/fs:sweep_time;         % sweep time matrix
c = 3e8;           
range = 24000;    
velocity = 50;  % velocity in m/s
fd = (2*trans_freq*velocity)/c;
% fd = 0;
td2 = 2*range/c;   % delay in seconds
fb = (2*b*range)/(sweep_time*c);
td = round((2*range/c)*fs);  % delay in number of samples w.r.to range
beat = sin(2*pi*fd*t);
z = zeros(1,td);

for i = 1:total_sweeps;
    if(mod(i,2)== 0)     
        tx_dn=chirp(t,b,sweep_time,0);
        tx((sweep_time*fs*(i-1)+i):sweep_time*fs*i+i) = tx_dn;  
        rx_dn=chirp(t,b+fd,sweep_time,0+fd);       
        rx((sweep_time*fs*(i-1)+i):sweep_time*fs*i+i) = rx_dn;
%         rx((sweep_time*fs*(i-1)+i):sweep_time*fs*i+i) = rx_dn;
        rx_4mix(i,:) = [z rx_dn];
        tx_4mix(i,:) = [tx_dn z];        
    else
        tx_up=chirp(t,0,sweep_time,b);% Start @ DC, cross 25MHz at t=3 millisec 
        tx((sweep_time*fs*(i-1)+i):sweep_time*fs*i+i) = tx_up;
        rx_up=chirp(t,0+fd,sweep_time,b+fd);% Start @ DC+fd, cross 25MHz at t=3 millisec 
        rx((sweep_time*fs*(i-1)+i):sweep_time*fs*i+i) = rx_up;
%         rx((sweep_time*fs*(i-1)+i):sweep_time*fs*i+i) = rx_up;
        rx_4mix(i,:) = [z rx_up];
        tx_4mix(i,:) = [tx_up z];
    end
end
rx = [z rx];

Answer 1

[Babak]

Use MATLAB coder to convert matlab code into C code.

[Mohsin]

i have to convert only these lines i cant afford to purchase the MATLAB CODER

[Jan]

This is obviously not trivial. Commands like chirp require a lot of work and even 0:1/fs:sweep_time is not trivial.

I assume a professional C programmer can convert this in 40 hours. But as usual for programming projects, the doubled time is realistic also.

Why do you want to convert this to C?