Axes OuterPosition going nuts

Okay, so I have an old GUIDE-created figure (with custom toolbar, which is the reason I still use it) containing 4 axes which I have sorted two-by-two. I have set the Figure and all Axes' units to normalized. The axes are displayed in the figure as shown below. When I request the Position or TightInset values I get the correct normalized values. However, when I request the OuterPosition for these axes I get some ridiculous values, see code below. When everything is set to normalized, why oh why am I getting these results. In fact; how should it even be possible that I get values outside the 0-1 range when all is set to normalized? Any ideas?

A(1:4).OuterPosition

ans =
 -110.8247  -54.7364  193.1601   92.5802
ans =
 -110.8247  -54.2364  193.1601   92.5802
ans =
 -111.3247  -54.7364  193.1601   92.5802
ans =
 -111.3247  -54.2364  193.1601   92.5802

Answer 1

[Jan]

When do you get these output position values? Before a drawnow or afterwards?

Please check again, if you are really checking the objects you thinks you are checking:

A(1).Color = [1,0,0]
drawnow
A(1).OuterPosition
A(1).Position
A(1).Units

[Sjouke Rinsma]

Thanks for replying Jan. As requested, see below.

>> A(1).Color = [1, 0, 0];
>> drawnow
>> A(1).OuterPosition
ans =
 -110.8247  -54.7364  193.1601   92.5802
>> A(1).Position
ans =
    0.5639    0.0836    0.3722    0.3828
>> A(1).Units
ans =
    'normalized'

When I change the outer position the following happens (look closely to see the tiny dot somewhere in the empty space at the bottom right).

    >> A(1).OuterPosition = [0.5 0 0.5 0.5]

[Sjouke Rinsma]

Okay, so I am to exuse myself... I made a boo boo.

It apparently did not come to mind I was mistaken in expecting all normalized positional values to be between 0 and 1... scaling doet not imply limiting when considering variables that depend on each other.

I'm working in a several thousand lines of code in which the setting of the axes to 'normalized' was accidentally preceded by a setting of the axes position to a normalized value (e.g. [0 0.5 0.5 0.5]). Because I additionally use a function that automatically sorts the axes layout for a given figure, the position value was again set to the normalized value ([0 0.5 0.5 0.5]) resulting in the OuterPosition becoming as indicated before.

[Jan]

I'm glad if your problem is solved. Debugging is a hard job, which can be solved with co-workers much easier.