issue with saving matrix in for loop
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Turbulence Analysis
el 29 de En. de 2021
Comentada: Turbulence Analysis
el 29 de En. de 2021
Hi,
I am creating a big matrix 'U' in the for loop as shown below. After this I have to avergae this matrix.
As long as, if my 'kk' is contonous i.e. from 1 to 10000, i dont have any issue. But, for sometimes, my 'kk' is discontinous, for e.g. 5, 7, 11, 18, 23, here logically I should get U matrix of a x b x 5, beacuse I have read only 5 files. However, I end up with a x b x 23, this changes my average value. Is there any way to get rid of this ??...
for kk = 1:1:10000
U(:,:,kk) = fu2;
end
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Respuesta aceptada
David Durschlag
el 29 de En. de 2021
The index being assigned to in your code is based on the loop variable (kk). If you assign to index 23, you will have a matrix with dimension at least 23, though it may be mostly empty.
By adding a second variable tracking your matrix index, you can reduce this dimension:
U = [];
index = 1
for kk = 1:3:10000
U(:,:,index) = fu2;
index = index + 1;
end
In this example code, I simulate your discontinuous kk by adding 3 each time instead of 1. The result is that U has dimension 3334 instead of 10000.
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