index exceed matrix dimensions

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Oday Shahadh on 10 Feb 2021
Commented: KALYAN ACHARJYA on 10 Feb 2021
Hi, every body
why I have an index exceed matrix dimesnions in this code, pls help
z1=linspace(0,D,1000);
z2=linspace(0,D1,1000);
z3=linspace(0,D2,1000);
z=[z1,z2,z3];
Dv=[D,D1,D2];
for j =1:3
p1i=(4*mu*N*I)/(pi*L);
p2i=1./((((z(j)./(L./2)).^2)+1).*sqrt(((z(j)./(L./2)).^2)+2));
p3i=1./(((((z(j)-D(j))./(L./2)).^2)+1).*sqrt((((z(j)-D(j))./(L./2)).^2)+2));
Bi=(p1i*(p2i+p3i))*10000;
end

KALYAN ACHARJYA on 10 Feb 2021
Edited: KALYAN ACHARJYA on 10 Feb 2021
Issue with this line
p3i=1./(((((z(j)-D(j))./(L./2)).^2)+1).*sqrt((((z(j)-D(j))./(L./2)).^2)+2));
You are trying to access D as a vector, is that so?
Also you used D in the following line also
z1=linspace(0,D,1000);
D might be scalar data (one numeric value), as per z1 statement
More: It may be typo mistake, D may be Dv, bacause you have defined Dv, but not use anywhere in the code.
KALYAN ACHARJYA on 10 Feb 2021
See the for loop j, 1 to 3 only. Note Dv having length 3 only