# How do I replace elements in a vector with other vectors?

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Cai Chin el 22 de Feb. de 2021
Respondida: Anmol Dhiman el 27 de Feb. de 2021
Hi, I am attempting to replace elements in the vectors seq1, 2 and 3 each with 12 numbers randomly chosen between 1 and 9. I have an array named rectColor1. I am trying to replace elements in the vectors seq1, 2 and 3 with the elements from the rectColor arrays. I have attempted to do so using the following code, but it keeps saying that there are an unequal number of elements on the left and right sides. How would I go about resolving this issue? Any help would be greatly appreciated, thanks in advance:
% Define grayscales
rectColor{1} = [0.1 0.1 0.1];
rectColor{2} = [0.15 0.15 0.15];
rectColor{3} = [0.22 0.22 0.22];
rectColor{4} = [0.30 0.30 0.30];
rectColor{5} = [0.40 0.40 0.40];
rectColor{6} = [0.55 0.55 0.55];
rectColor{7} = [0.7 0.7 0.7];
rectColor{8} = [0.85 0.85 0.85];
rectColor{9} = [1 1 1];
trialorder = [1 2 3 4];
randtemp = Shuffle(trialorder);
% Define distributions
if randtemp(currenttrialinblock) == 1 % No mean difference (control)
seq1 = dis(1, 5, 9, 1, 12);
seq2 = dis(4, 5, 9, 1, 12);
seq3 = dis(1, 5, 9, 1, 12);
elseif randtemp(currenttrialinblock) == 2 % Small mean difference
seq1 = dis(1, 4, 9, 1, 12);
seq2 = dis(4, 5, 9, 1, 12);
seq3 = dis(1, 6, 9, 1, 12);
elseif randtemp(currenttrialinblock) == 3 % Large mean difference
seq1 = dis(1, 3, 9, 1, 12);
seq2 = dis(1, 5, 9, 1, 12);
seq3 = dis(1, 7, 9, 1, 12);
elseif randtemp(currenttrialinblock) == 4 % No mean difference (manipulation)
seq1 = dis(1, 5, 9, 1, 12);
seq2 = dis(4, 5, 9, 1, 12);
seq3 = dis(1, 5, 9, 1, 12);
end
% Substitute numbers for grayscale images
for i = 1:12
seq1(i) = rectColor{seq1(i)};
end
for i = 1:12
seq2(i) = rectColor{seq2(i)};
end
for i = 1:12
seq3(i) = rectColor{seq3(i)};
end
function x = dis(va, mu, ul, ll, nvals)
n = makedist('Normal','mu', mu,'sigma',sqrt(va));
t = truncate(n,ll,ul);
x = floor(random(t,nvals,1) + 0.5);
end
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### Respuestas (1)

Anmol Dhiman el 27 de Feb. de 2021
Hi Cai,
In the above code, rectColor is of type cell whereas seq(1) is of type double. You can verify using
class(rectColor)
To solve the above error you can convert rectColor(i) into array using cell2mat.
seq1(i) = cell2mat(rectColor{seq1(i)});
Hope it Helps
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