Find first index that exceeds condition

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Jonathan Cheong
Jonathan Cheong el 25 de Feb. de 2021
Comentada: Jonathan Cheong el 25 de Feb. de 2021
To elaborate and ensuring my questions are specific, I have a dataset and their index:
[1,2,3,4,5,6,7,8,9]
[1,4,8,0,0,1,9,0,3]
Say I would like to find the index and value of the 1st value > 2 after value (8)
Which means my desired output would look like this:
[7]
[9]
Normally, I would have a table of starting indices, but this is just a random sample to keep it short.
How do I code this?
Thanks.

Respuestas (1)

KALYAN ACHARJYA
KALYAN ACHARJYA el 25 de Feb. de 2021
"I would like to find the index and value of the 1st value > 2 after value (8)"
Is this?
data=[1,4,8,0,0,1,9,0,3]
idx8=find(data==8)
idx=find(diff(data)<0)
result_idx=idx(idx>idx8(1))
Answer would be 7 only, can you verify again?
  2 comentarios
Jonathan Cheong
Jonathan Cheong el 25 de Feb. de 2021
Hey Kalyan, thanks for the answer.
Although it technically produces the correct output, it's more like hard coded.
Is there a method to code so that it applies across an entire array consistently?
For example I have attached files: starting index (fdd2), data (rain2).
Same situation just in the format of an array.
Jonathan Cheong
Jonathan Cheong el 25 de Feb. de 2021
The data won't be exactly 0 but it will be less than 2.
Hence the code should stop when the 1st value greater than 2 after the starting index is reached

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