Taking a descend interval

for t=1:n
    [L(t)]=(1/(50)^(t))
    [C(t)]=(1/(800))^(t);
end

For the 1st line (L(t)) i need to use the interval 1:n however for the 2nd line i need from n:1. How do i change t without changing the interval in the for loop?

Answer 1

[Alan Stevens]

Insert

tau = n+1-t;

then raise 1/800 to the power tau.

[Jane Smith]

Worked perfectly! Thanks