matrix array

Dear Sir I need some help for matrix array. I have matrix 23x2 like this: 12 0 8 0 4 0 1 0 5 0 9 0 3 0 1 0 10 0 12 0 2 5 4 7 6 9 8 11 2 3 6 7 10 11 1 2 3 4 5 6 7 8 9 10 11 12

 And I would like to separate it to two matrixes
1) With zeros in second Colum:
  A=
    12     0
     8     0
     4     0
     1     0
     5     0
     9     0
     3     0
     1     0
    10     0
    12     0
2) Without zeros in second Colum:
B=
     2     5
     4     7
     6     9
     8    11
     2     3
     6     7
    10    11
     1     2
     3     4
     5     6
     7     8
     9    10
    11    12

I have been used, nonzero but it will change my dimension to only one column. I need only non zeros in second Colum   and value in first Colum that correspond to non-zeros in second Colum.
 Anyone can suggest me please.

 Thank you very much

Answer 1

[Jarrod Rivituso]

Would reshape followed by transpose do the trick....

%Create data array
data = [12 0 8 0 4 0 1 0 5 0 9 0 3 0 1 0 10 0 12 0 2 5 4 7 6 9 8 11 2 3 6 7 10 11 1 2 3 4 5 6 7 8 9 10 11 12]

%Reshape, then transpose
A = reshape(data(1:20),2,10)'
B = reshape(data(21:46),2,13)'

Answer 2

[Andrei Bobrov]

variant

A = [12 0 8 0 4 0 1 0 5 0 9 0 3 0 1 0 10 0 12 0 ...
     2 5 4 7 6 9 8 11 2 3 6 7 10 11 1 2 3 4 5 6 7 8 9 10 11 12];
N =find(A==0,1,'last');
A1 = reshape(A(1:N),2,[])';
A2 = reshape(A(N+1:end),2,[])';

If the matrix Ainput is as follows:

 Ainput = [12     0
8     0
4     0
1     0
5     0
9     0
3     0
1     0
10     0
12     0
2     5
4     7
6     9
8    11
2     3
6     7
10    11
1     2
3     4
5     6
7     8
9    10
11    12];

then

N = find(all(Ainput,2),1,'first')-1
A1 = Ainput(1:N,:)
A2 = Ainput(N+1:end,:)

if

Ainput = [12     7
     0     6
     8     9
     0     8
     4    11
     0     2
     1     3
     0     6
     5     7
     0    10
     9    11
     0     1
     3     2
     0     3
     1     4
     0     5
    10     6
     0     7
    12     8
     0     9
     2    10
     5    11
     4    12]

as at the beginning of this an answer