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for loop reference solution (from coursera) question

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Sara Ismail-Sutton
Sara Ismail-Sutton on 14 Mar 2021
Answered: Shubham Rawat on 17 Mar 2021
Sorry if this is a stupid question, but I am pretty new to matlab, looking at this solution at the loop "for n=1:nint@" I can't see how this works as there isn't a variable allocated "n", just "nx" and "ny". and the other functions in the loop are functions of 'Z' or 'z'.
Many thanks for your help.
  1 Comment
Russel Burgess
Russel Burgess on 14 Mar 2021
The for loop expression creates the variable, i.e.,
for n=1:nit
Will create a variable, n, initially set to 1. n is persistent, i.e., it will still exist after the foor loop is done - with the value nit, assuming nothing caused the for loop to break out early.

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Answers (1)

Shubham Rawat
Shubham Rawat on 17 Mar 2021
Hi Sara,
Comment is correct only inside for loop the variable n is instantiated.
You may look into this documentation for further help:
Hope this Helps!

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