Turning a function into anonymous function

2 views (last 30 days)
Maja Zdulska
Maja Zdulska on 17 Mar 2021
Commented: Maja Zdulska on 17 Mar 2021
Hi everyone,
I have this piece of code:
T_0 = 100; % initial temperature (deg C)
T_a = 10; % temperature of water used for cooling (deg C)
k = 0.034; % constant (dimensionless)
dt = 1; % temporal step (min)
Ts = 120; % prediction timespan (min)
t = [0:dt:Ts]; %temporal grid vector
%analytical solution
T_an1 = T_a+(T_0-T_a)*exp(-k*t);
T_an2 = @(t)T_a+(T_0-T_a)*exp(-k*t);
I would like to turn the function into anonymous (T_an2). Something is missing in the last line of the code, but I can't figure out what it is.
Any advice?

Answers (1)

Alan Stevens
Alan Stevens on 17 Mar 2021
What do you think is wrong with it? It works ok. Add
plot(t,T_an2(t)),grid
at the end to see the result.
  1 Comment
Maja Zdulska
Maja Zdulska on 17 Mar 2021
Oh, I think I was misleaded by the way it came out in the workspace.
Thanks anyway!

Sign in to comment.

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by