Detect the error position in a vector and correct it (Matlab)

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Dear members;
I have the code word C of length 'M' and I have also the received vector V after decoding of the same length 'M' as C
For example:
V=[1 0 0 1 0 1 0 1 0 0]
C=[1 1 0 1 0 0 0 1 0 0]
I want firstly detecting the position of each bold bit of V and than correct it by adding 1 to those bits (because in mod2: 0+1=1 and 1+1=0) in order to obtain V=C
How can I do that please
  4 comentarios
Adam Danz
Adam Danz el 18 de Mzo. de 2021
> I want firstly detecting the position of each bold bit of V
Ah, so what you really want to do is find the index of the vector where V(i) is not equal to C(i).
Afluo Raoual
Afluo Raoual el 18 de Mzo. de 2021
Exactly yes, and then correct the bold bits of V in order to obtain them equal to C

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Christopher McCausland
Christopher McCausland el 18 de Mzo. de 2021
Hi Afluo,
You can try something like the below to assess where the diffrences between the arrays are; after this just cycle to these locations and change the value as you need.
I hope this helps,
Christopher
V=[1 0 0 1 0 1 0 1 0 0]
C=[1 1 0 1 0 0 0 1 0 0]
diff_Check = V ~= C;
  4 comentarios
Adam Danz
Adam Danz el 18 de Mzo. de 2021
Editada: Adam Danz el 18 de Mzo. de 2021
I agree with Christopher McCausland , this does describe what you want to do but is missing the final step which is quite straightforward and something you could fill in yourself,
V=[1 0 0 1 0 1 0 1 0 0];
C=[1 1 0 1 0 0 0 1 0 0];
V(V~=C) = V(V~=C) + 1;
mod(V,2)
ans = 1×10
1 1 0 1 0 0 0 1 0 0
Afluo Raoual
Afluo Raoual el 18 de Mzo. de 2021
Thank you so much. It works

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