addition , subtraction

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nand mourya
nand mourya el 19 de Mayo de 2011
[EDIT: 20110519 14:45 CDT - reformat - WDR]
Hi, I need help in coding the following example.. thanks
S is (mXn) matrix and d is (mX1) array
S(1,:) = [0 0.2 0.3 0.5 0.6 0.7 0.72 0.75 ...... 1 ]
for example length(S(1,:)) = odd (lets say 7)
d(1)= S(1,1) + (S(1,3)-S(1,2))+(S(1,5)-S(1,4))+(S(1,7)-S(1,6))
...and so on...
if length(S(1,:)) = even(lets say 8)
d(1)=S(1,1) + (S(1,3)-S(1,2))+(S(1,5)-S(1,4))+(S(1,7)-S(1,6))
i.e. neglect S(1,8)
I want to run this program in a loop for entire S matrix and find the array d

Respuesta aceptada

Walter Roberson
Walter Roberson el 19 de Mayo de 2011
d = Sum(S(:,1:2:end),2) - Sum(S(:,2:2:end-1),2)
  2 comentarios
Andy
Andy el 19 de Mayo de 2011
Ninja'd! Walter, you need lower case sums.
Walter Roberson
Walter Roberson el 19 de Mayo de 2011
Good point, Andy. I've been flipping between programming languages too much.

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