Can anyone help me plot the graph for below equation using matlab code?

[Gowtham Kumar Ganji]

This is heat flow in welding equation from RS Parmar.

[Sara Boznik]

Do you have some code in context?

[Gowtham Kumar Ganji]

yes

Answer 1

[Walter Roberson]

Pi = pi;   %use Pi = sym(pi) if you want to work symbolic

T = T_0 + Q_p./(2.*Pi.*k) .* exp(-lambda.*nu.*xi) .* exp(-lambda.*nu.*R)./R

I wonder why they did not combine the exp() ? exp(-lambda.*nu.*(xi+R))./R

[Walter Roberson]

Pi = sym(pi);   %use Pi = sym(pi) if you want to work symbolic

T_0 = 300;
Q_p = rand() * 1000;
k = rand() * 10;
lambda = rand() / 100;
nu = rand();

Lxi = 2./(lambda*nu);
Uxi = 1./(lambda*nu);

syms xi R
T = T_0 + Q_p./(2.*Pi.*k) .* exp(-lambda.*nu.*xi) .* exp(-lambda.*nu.*R)./R

T = 

fsurf(T, [1e-1 1 0 12]); xlabel('R'); ylabel('\xi');

[Walter Roberson]

E=-50*10^-3; %units m
y=15*10^-3; %units m
z=0; %units m
R= sqrt(E^2+y^2+z^2); %units m
k=64.167; %units J/min.sec.C
Q_p=2340; %units J/sec
lambda=28800;
nu=0.002083; %units m/sec
T_0=20; %unit C

Pi = sym(pi);   %use Pi = sym(pi) if you want to work symbolic
syms xi

T = T_0 + Q_p./(2.*Pi.*k) .* exp(-lambda.*nu.*xi) .* exp(-lambda.*nu.*R)./R

T = 

Lxi = 1./(lambda*nu);
Uxi = 2./(lambda*nu);

fplot(T, [Lxi, Uxi])