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Strings with changing length and cases

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JP
JP el 19 de Jun. de 2013
Hi, Im trying to make the following code work and it just wont seem to do what I want. NOTE - The string length of my variable is changing so for different cases I want a different interval.
Astr = '123456789'
switch Astr
case strcmp(Astr([2:4,5:7]), '234567' )
x = 5
case strcmp(Astr([3:6,6:8]), '789123' )
x = 6
case strcmp(Astr([1:3,4:6]), '912345' )
x = 7
otherwise
x = 8
end
I think it has to do with the way Im defining the string values, it keeps outputting x = 8 (the otherwise case). Please let me know how to fix thanks!

Respuesta aceptada

Azzi Abdelmalek
Azzi Abdelmalek el 19 de Jun. de 2013
It's more appropriate to use IF statement
Astr = '123456789'
if isequal(Astr([2:4,5:7]), '234567' )
x = 5
elseif isequal(Astr([3:6,6:8]), '789123' )
x = 6
elseif isequal(Astr([1:3,4:6]), '912345' )
x = 7
else
x = 8
end

Más respuestas (2)

Iain
Iain el 19 de Jun. de 2013
Assuming that you've shown us "everything". Theres a better way:
x = 8 - (Astr(3) == '2') - 2*(Astr(3) == '7') - 3*(Astr(3) == '3');
  2 comentarios
JP
JP el 19 de Jun. de 2013
Well I havent shown everything...I was just using this as a simpler example for a more complex code Im working on....
Iain
Iain el 19 de Jun. de 2013
Azzi's solution is correct, but it will be easy to get lost in it, and make logical errors.

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Jan
Jan el 19 de Jun. de 2013
This case can never happen:
strcmp(Astr([3:6,6:8]), '789123' )
One string has 7 character with a repeated sixth element, while the other string has 6 characters only without a repetition.

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