How I can optimize my code for a stack construct?

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Nazar Adamchuk
Nazar Adamchuk el 19 de Abr. de 2021
Comentada: Rik el 19 de Abr. de 2021
In reality I have nine variables with scalar values. For them, I have built a stack construct (last in first out) with following logic: push (only for three variabled from nine, as an example)
stack(end+1:end+3) = [value1, value2, value3];
read and pop is
value3 = stack(end); stack = [];
value2 = stack(end); stack = [];
value1 = stack(end); stack = [];
In my script I call these code lines over 8 million time each and that is why I wish the time could be less. Can you help me to optimize the code lines and decrease the speed?

Respuestas (1)

Rik
Rik el 19 de Abr. de 2021
Dynamically growing a variable is generally slow, because Matlab needs to copy the entire array.
You could pre-allocate a stack and use a counter to keep track of the position in the stack.
  2 comentarios
Nazar Adamchuk
Nazar Adamchuk el 19 de Abr. de 2021
I am not copying the array, I am appending the elements to the array. That would be copying:
stack = [stack value1 value2 value3]
Rik
Rik el 19 de Abr. de 2021
Matlab is copying the array for you: if you add an element to a vector Matlab will allocate a new block of memory, copy all the data (appending your new elements), and free the old memory blocks.
%these two operations are the exact same:
stack(end+1:end+3) = [value1, value2, value3];
stack = [stack, value1, value2, value3];

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