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How to change x-axis values from iteration to time?

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Khan
Khan el 26 de Abr. de 2021
Comentada: Khan el 26 de Abr. de 2021
Hello,
I have a simple problem. I have generated a matrix called "A" (2000 by 1970). The rows of the matrix are velocity vectors while the columns represents the iteration numbers. In other words, the row vectors values are changing with iteration. A simple plot is given in the picture.
let's plot row number 277 of the given matrix,
figure (1)
plot(1:1970, A(277,:))
Now I would like to plot the same row vectors against the time (time on x-axis). The intial time is zero, final time should be 1.970 with time interval 0.001.
Can someone recomend how can I do it. Thank you.

Respuesta aceptada

Walter Roberson
Walter Roberson el 26 de Abr. de 2021
dt = 0.001;
time = (0:size(A,2)-1) * dt;
plot(time, A(277,:));
Note that the final value will be 1.969 not 1.970 since your time starts at 0.
  3 comentarios
Walter Roberson
Walter Roberson el 26 de Abr. de 2021
To get exactly 1.970 with dt 0.001 and starting from 0, you would need your A to have 1971 columns instead of 1970.
Khan
Khan el 26 de Abr. de 2021
Ok, Thank you.

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