Filling array with dec2hex() value

Hello,

I have an issue with fill my matrix after the use of dec2hex() function.

As the first step, I allocate space for a three-column matrix. The next step is to generate a random number and delete the decimal part of the number. Which are saved to the first column of matrix. In the last step, I want to converse decimal value to hexadecimal value by dec2hex() function. The conversion to show me basic error: " Unable to perform assignment because the size of the left side is 1-by-1 and the size of the right side is 1-by-2." Is the problem with the output of the dec2hex() function?

Could you help me with the issue?

%%allocation memory for matrix
for n=1:len
    data_extend(n,1) = 0;
    data_extend(n,2) = 0;
    data_extend(n,3) = 0;
end

%randomize fill of data_extend array
    a = 0;
    b = 255;    
for n=1:len
    data_extend(n,1) = (b-a).*rand(1,1) + a;    %%rand number from interval 0-255;  a-b
    data_extend(n,1) = floor(data_extend(n,1));  %%delete decimal
end

%%conversion decimal to hex
for n=1:len
    data_extend(n,3) = dec2hex(data_extend(n,1));
end

Answer 1

[DGM]

Observe that the output of dec2hex() is a character array:

x = 123
hx = dec2hex(x)

gives

x =
   123
hx =
    '7B'

So in this example, the input is scalar numeric, but the output is 1x2 char. Not only is the size mismatched, they aren't the same datatype. You'll have to come up with a different way of storing the output -- a cell array or something.

[per isakson]

%% allocation memory for matrix
data_extend = zeros(len,3);

[Robert Plsicik]

@DGM Thank you for you helpfully answer.

@per isakson I know the method, which you mentioned, however the matlab is not my primary programing language, sometimes I can't think of some matlab functions. Thank you for the reminder.