Urgent: How do I perform FFT on a time signal
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I have a vibration time signal am working on. I am finding it difficult to write the code to perform fft on it. Could anyone help with it please? The length of the signal is 40000 while the sampling frequency is 20000.
Additionally, how are the length of the signal and sampling frequency arrived at?
2 comentarios
Youssef Khmou
el 26 de Jul. de 2013
Jan
el 31 de Jul. de 2013
While this question might be "urgent" for you, it is not "urgent" for all readers. Therefore it is recommended toavoid such pushing terms.
Respuestas (3)
dpb
el 26 de Jul. de 2013
0 votos
doc fft
Sampling frequency is set by the hardware, time then determines the length.
Youssef Khmou
el 26 de Jul. de 2013
Editada: Youssef Khmou
el 26 de Jul. de 2013
hi, given your signal X,
Fs=2e+4;
Resolution=512;
Ts=1/Fs;
N=4e+4;
T=N*Ts;
Fx=abs(fft(X,Resolution));
Frequency=(0:Resolution-1)*Fs/Resolution;
figure, plot(Frequency(1:end/2),Fx(1:end/2)); % two sided to one side
Hi, just use the following code:
fs=20000; % sampling frequency
N=40000; % length of signal
dF=Fs/N;
f=-Fs/2:dF:Fs/2-dF; %remember nyquist frequency?
plot(f,abs(fftshift(fft(<your signal>)/N)));
Hope this helps!
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