Lagrange Interpolation related problem (plotting a graph)
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x = input('Enter values of x: ');
y = input('Enter values of y: ');
n = length(x);
L = zeros(n,n);
for i = 1:n
V= 1;
for j = 1:n
if i~= j
V = conv(V,poly(x(j)))/(x(i) - x(j));
end
end
L(i,:) = V*y(i);
end
L
P = sum(L)
Now here I want to plot the graph of a certain method, But don't know how to do it!
Respuestas (1)
Sulaymon Eshkabilov
el 29 de Mayo de 2021
Hi
The answer is simple:
plot(x, L(1,:)) OR plot(x, L(2,:))
plot(x, V) or plot(x, P)
Or within the loop:
...
if i~= j
V = conv(V,poly(x(j)))/(x(i) - x(j));
end
end
L(i,:) = V*y(i);
plot(x, L(i,:)), hold all
end
4 comentarios
Maha Aftab
el 29 de Mayo de 2021
Sulaymon Eshkabilov
el 29 de Mayo de 2021
The number of values entered for x and y are equal or not?
Make sure that they have equal number of value entries via input().
Maha Aftab
el 30 de Mayo de 2021
Sulaymon Eshkabilov
el 30 de Mayo de 2021
Test again:
x = input('Enter values of x: ');
y = input('Enter values of y: ');
n = length(x);
L = zeros(n,n);
for i = 1:n
V= 1;
for j = 1:n
if i~= j
V = conv(V,poly(x(j)))/(x(i) - x(j));
end
end
L(i,:) = V*y(i);
plot(x, L(i,:)), hold all
end
x = linspace(0, 5);
y = linspace(0, 5)*2+linspace(0, 5).^2;
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