structures consolidation and manipulations

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hdg D
hdg D el 21 de Ag. de 2013
Hello I have a basic question on structures I have a struct a which can contain n fields So for example
a(1)
=
mydata:[135x6]
myid:{1x6}
mydates = [135x1]
mytel=
myname=
etc
and so on for a(2), a(3)...etc to m
I want to then do some manipulation on the data say my own function transform which takes a(1) as an input and produces a(1).stats
Then I want to consolidate all my m objects into one big structure say BigStruct that has all the fields that a had plus the stats
such that
BigStruct =
mydata =[135x1000]
mydates = [135x1000]
etc
etc
Again I am doing all this in a for loop and was wondering if there is an easier elegant method to do this
Thanks so much
  2 comentarios
Azzi Abdelmalek
Azzi Abdelmalek el 21 de Ag. de 2013
Are you looking for elegant way or fastest way?
Azzi Abdelmalek
Azzi Abdelmalek el 21 de Ag. de 2013
Editada: Azzi Abdelmalek el 21 de Ag. de 2013
You did not specify if the concatenation is always horizontal or vertical?

Iniciar sesión para comentar.

Respuesta aceptada

Walter Roberson
Walter Roberson el 21 de Ag. de 2013
Tstats = arrayfun( @(K) yourStats(a(K)), 1:length(a), 'Uniform', 0);
T1 = struct2cell(a(:));
T2 = cat(2, T1);
T3 = horzcat(T2, Tstats);
Now use cell2struct() or the like to convert 32 back into a cell with appropriate field names e.g. [fieldnames(a); {'stats'}]
Watch out though for the dimension you concatenate on for mydata: somehow you went from 1000 of (135 x 6) to a single 135 x 1000 leaving us uncertain what happened to the x 6.

Más respuestas (1)

Azzi Abdelmalek
Azzi Abdelmalek el 21 de Ag. de 2013
Editada: Azzi Abdelmalek el 21 de Ag. de 2013
For vertical concatenation
names=fieldnames(a);
for k=1:numel(names)
b.(names{k})=cat(1,a(:).(names{k}));
end
b

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