What's the problem in my loop?

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Febin Benjamin
Febin Benjamin el 30 de Ag. de 2013
A=imread('cameraman.tif');
B=zeros(255,255);
for j=0:255
for k=0:255
B(j,k)=A(j,k+1)-A(j,k-1);
end
end
figure,imshow(B);
error: Attempted to access A(0,1); index must be a positive integer or logical.
Error in tryfebin (line 6)
B(j,k)=A(j,k+1)-A(j,k-1);
  1 comentario
Jan
Jan el 30 de Ag. de 2013
The error message is very meaningful: "index must be a positive integer or logical"

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Respuesta aceptada

David Sanchez
David Sanchez el 30 de Ag. de 2013
Your code should go like this:
A=imread('cameraman.tif');
B=zeros( size(A) );
for j=1:size(A,1)
for k=2:(size(A)-1) %edge pixels of B matrix has to be treated differently
B(j,k)=A(j,k+1)-A(j,k-1); %you can not apply this algorithm to edge pixels
end
end
figure,imshow(B);

Más respuestas (1)

ES
ES el 30 de Ag. de 2013
Matlab Matrices do not have indices starting at 0. There is nothing like A(0) in MATLAB (But it is so in C or Python though). This is a common issue faced by people migrating from C or Python to MATLAB.
Solution: Your for loop with j should run from 1 to 256.

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