HOW TO FILTER AN HOUR DATA FROM ARRAY OF DAILY,MONTHLY AND YEAR DATA
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I HAVE DATA WITH FOLLOWING COLUMN: DATE, TIME, S/N, VALUES AS SHOWN IN THE ATTACHED FILE. KINDLY HELP ME WITH CODE TO SEPARATE THE DATA INTO DIFFERENT HOURS SUCH AS 7.30, 8.30, ..., 15.30 AND DIFFERENT MONTHS, JANUARY, FEBRUARY, ... THANKS.
OJO O.S. ojoso@futa.edu.ng
2 comentarios
Scott MacKenzie
el 19 de Jun. de 2021
What do you mean by "separate"? Do you want the data sorted by hour, or sorted by month? Or something else?
Respuestas (1)
Scott MacKenzie
el 19 de Jun. de 2021
Editada: Scott MacKenzie
el 22 de Jun. de 2021
T = readtable('https://www.mathworks.com/matlabcentral/answers/uploaded_files/658625/SAMPLE%20DATA.xlsx');
% combine DATE and TIME columns and replace as single DateTime column
DateTime = T.DATE + T.TIME;
DateTime.Format = 'yyyy-MM-dd HH:mm';
T = [table(DateTime) T(:,3:end)];
% for sorting, create separate columns for year, month, and hour
T.Year = year(T.DateTime);
T.Month = month(T.DateTime);
T.Hour = hour(T.DateTime);
yearColumn = find(string(T.Properties.VariableNames) == "Year");
monthColumn = find(string(T.Properties.VariableNames) == "Month");
hourColumn = find(string(T.Properties.VariableNames) == "Hour");
% sort by month
T1 = sortrows(T, monthColumn);
% sort by hour
T2 = sortrows(T, hourColumn);
% sort by hour, separately within each year
T3 = sortrows(T, [yearColumn hourColumn]);
4 comentarios
Scott MacKenzie
el 21 de Jun. de 2021
Converting to a double array is simple except for the 1st column, since the data in the 1st column are DateTime.
If you just want the numeric data, which start in the 2nd column, then
T{:,2:end}
If you want to include the DateTime information, it must be converted to a serial date number. This will do the trick:
[datenum(T.DateTime) T{:,2:end}]
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