looping for a function
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Hi, can I apply
[output1, output2] = calculate(b);
in a 3D data such as 80x30x400 data?
2 comentarios
KSSV
el 23 de Jun. de 2021
It depends on your function calculate.
Nurul Ain Basirah Zakaria
el 23 de Jun. de 2021
Respuestas (2)
KSSV
el 23 de Jun. de 2021
This is what you are looking for?
[m,n,p] = size(b) ; % b is matrix of size 80x30x400
iwant = zeros(p,2);
for i = 1:p
[output1, output2] = calculate(b(:,:,i));
iwant(i,:) = [output1, output2] ;
end
6 comentarios
Nurul Ain Basirah Zakaria
el 23 de Jun. de 2021
Editada: KSSV
el 23 de Jun. de 2021
KSSV
el 23 de Jun. de 2021
What is drought? There is no function or variable on this name, so the error.
Nurul Ain Basirah Zakaria
el 23 de Jun. de 2021
KSSV
el 23 de Jun. de 2021
That case function is not present in the folder you are working. Keep the function in the pwd or add path of the function.
Nurul Ain Basirah Zakaria
el 23 de Jun. de 2021
KSSV
el 23 de Jun. de 2021
There is no output called duration in drought.
Walter Roberson
el 23 de Jun. de 2021
This has nothing to do with a missing function.
Your code in drought.m is defined to expect at least four output variables -- otherwise you would have received an error about too many output arguments before you reached the error you did.
Your code in drought.m assigns some value to the first of the output variables it assigns.
However, your code in drought.m does not assign any value to the second of the output variables it assigns.
At the moment we do not have enough information to know whether drought.m never assigns to the second output variable, or if instead it does not assign to the second output variable under some conditions and the conditions happen to be such that it does not assign.
For example,
function [A, B, C] = drought(data)
if any(data(:) < 0 %negative rainfall ??
A = nan; %signal invalid data
return
end
A = mean(data);
B = std(data);
c = var(data);
end
In this example code, B is not assigned to if there are any negative values in the input, and C is never assigned to under any conditions. In this example code it could well be the case that the intention was to assign to C instead of c, but MATLAB doesn't know anything about intentions.
2 comentarios
Nurul Ain Basirah Zakaria
el 23 de Jun. de 2021
Walter Roberson
el 24 de Jun. de 2021
We have not seen your function drought so it is difficut to say why it is failing.
Could you confirm that it is failing when the input is a 1 x 1 x Something array (such as 1 x 1 x 400) ?
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